TixFix
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2 changed files with 4 additions and 4 deletions
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@ -124,7 +124,7 @@ zu können und diese so in Relation zu setzen definieren wir Funktoren.
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sodass $\mathcal{F}(f\circ g)=\mathcal{F}(f)\circ\mathcal{F}(g)$
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sodass $\mathcal{F}(f\circ g)=\mathcal{F}(f)\circ\mathcal{F}(g)$
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\end{itemize}
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\end{itemize}
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\begin{center}
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\begin{center}
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\begin{tikzpicture}
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\begin{tikzpicture}[baseline=-15mm]
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\node(A) at (0,0){$A$};
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\node(A) at (0,0){$A$};
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\node(C) at (0,-3){$C$};
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\node(C) at (0,-3){$C$};
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\node(B) at (1,-1.5){$B$};
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\node(B) at (1,-1.5){$B$};
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@ -135,10 +135,10 @@ zu können und diese so in Relation zu setzen definieren wir Funktoren.
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(B) edge node[right]{$g$} (C)
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(B) edge node[right]{$g$} (C)
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;
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;
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\end{tikzpicture}
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\end{tikzpicture}
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\hspace{10mm}
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\hspace{5mm}
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Wird vom Funktor abgebildet auf
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Wird vom Funktor abgebildet auf
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\hspace{10mm}
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\hspace{5mm}
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\begin{tikzpicture}
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\begin{tikzpicture}[baseline=-15mm]
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\node(A) at (0,0){$\mathcal{F}(A)$};
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\node(A) at (0,0){$\mathcal{F}(A)$};
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\node(C) at (0,-3){$\mathcal{F}(C)$};
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\node(C) at (0,-3){$\mathcal{F}(C)$};
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\node(B) at (1,-1.5){$\mathcal{F}(B)$};
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\node(B) at (1,-1.5){$\mathcal{F}(B)$};
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